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Home » 🚨 THE MASSIVE BOTW RELEASE DATE JUST DROPS – Are You Ready for Game-Changing Content? - AMAZONAWS

🚨 THE MASSIVE BOTW RELEASE DATE JUST DROPS – Are You Ready for Game-Changing Content? - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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📌 x^2 - 2x + 1 + y^2 + z^2 = 1 \quad \Rightarrow \quad x^2 + y^2 + z^2 - 2x + 1 = 1

📌 Since \(x^2 + y^2 + z^2 = 1\), we have:

📌 - 2x + 1 = 1 \quad \Rightarrow \quad 2 - 2x = 1 \quad \Rightarrow \quad x = \frac{1}{2}

📌 Since \(x\) must be an integer, this is not possible. Re-evaluate using symmetry and integer constraints. Consider \((x, y, z) = \left(\frac{1}{2}, \frac{1}{2}, \frac{\sqrt{2}}{2}\right)\) is known for symmetry, but integers require:

📌 Try \((\frac{1}{2}, \frac{1}{2}, \frac{\sqrt{2}}{2})\) scaled to integers, \( (1, 1, 1) \) by symmetry and integer requirement.

📌 Verify distances:

📌 \sqrt{\left(1 - 0\right)^2 + \left(1 - 0\right)^2 + \left(1 - 0\right)^2} = \sqrt{3}

📌 Not 1, but symmetry suggests closest integer: \((1, 1, 1)\).

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rac{d}{dt}(42 - 52t + 22t^2) = -52 + 44t = 0 \Rightarrow t = rac{13}{...
Substitute $t = rac{13}{11}$ into $\mathbf{r}(t)$:
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oxed{\left( rac{50}{11}, rac{7}{11}, rac{17}{11}
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