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Home » Baddragon Is Here: The Untold Story Behind Its Viral Rise & Crazy Powers! - AMAZONAWS

Baddragon Is Here: The Untold Story Behind Its Viral Rise & Crazy Powers! - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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📌 This is a quadratic function in vertex form. The vertex occurs at \( x = -\frac{b}{2a} = -\frac{20}{2(-2)} = 5 \).

📌 So maximum profit occurs when \( x = 5 \), i.e., 500 units.

📌 Plug into \( P(x) \): \( P(5) = -2(25) + 20(5) - 30 = -50 + 100 - 30 = 20 \).

📌 Thus, maximum profit is $20,000.

📌 #### Maximum profit: $20,000 at 500 units

📌 The sum of the first \( n \) terms of an arithmetic sequence is \( S_n = 3n^2 + 5n \). Find the 10th term.

📌 The \( n \)-th term is \( a_n = S_n - S_{n-1} \).

📌 \( S_{10} = 3(100) + 5(10) = 300 + 50 = 350 \)

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First, solve the first two congruences:
Let \( k = 5a + 3 $. Substitute into the second:
5a + 3 \equiv 4 \pmod{7} \implies 5a \equiv 1 \pmod{7}
Multiply both sides by the modular inverse of 5 modulo 7. Since \( 5 \...
a \equiv 3 \cdot 1 = 3 \pmod{7} \implies a = 7b + 3
k = 5(7b + 3) + 3 = 35b + 15 + 3 = 35b + 18
So \( k \equiv 18 \pmod{35} \)
Now include the third congruence: \( k \equiv 2 \pmod{9} \)
Let \( k = 35b + 18 \). Then:
35b + 18 \equiv 2 \pmod{9}

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