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Home » Here, \( heta = rac\pi6\), \(n = 6\): - AMAZONAWS

Here, \( heta = rac\pi6\), \(n = 6\): - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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4^2 = 10 + 2ab \Rightarrow 16 = 10 + 2ab \Rightarrow 2ab = 6 \Rightarr...
Now compute \( |a - b| \). Note:
|a - b|^2 = (a - b)(\overline{a} - \overline{b}) = |a|^2 - a\overline{...
But better to use algebra:
|a - b|^2 = (a - b)^2 \quad ext{if real, but not necessarily.}
|a - b|^2 = (a - b)(\overline{a} - \overline{b}) = |a|^2 + |b|^2 - a\o...
Not helpful unless complex conjugates known.
Alternate: treat \( a \) and \( b \) as roots of quadratic:
x^2 - (a + b)x + ab = 0 \Rightarrow x^2 - 4x + 3 = 0
Roots: \( x = rac{4 \pm \sqrt{16 - 12}}{2} = rac{4 \pm 2}{2} = 3, 1...

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