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📅 March 5, 2026 👤 scraface

Mar 05, 2026

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Square and add the equations:
\[ (a \sin(c))^2 + (a \cos(c))^2 = (-1)^2 + 1^2 \]
\[ a^2 (\sin^2(c) + \cos^2(c)) = 1 + 1 = 2 \]
\[ a^2 = 2 \quad \Rightarrow \quad a = \sqrt{2} \]
With \( a = \sqrt{2} \), use:
\[ \sqrt{2} \sin(c) = -1 \quad \Rightarrow \quad \sin(c) = -\frac{1}{\...
\[ \sqrt{2} \cos(c) = 1 \quad \Rightarrow \quad \cos(c) = \frac{1}{\sq...
These values correspond to \( c = -\frac{\pi}{4} \) (since \(\sin(c) =...
Find \( b \):
The period of the function is \( \frac{2\pi}{b} \). Since \( f\left(\f...

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