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Home » Loam: \( 0.4 \times 80 = 32 \, \textkg \) - AMAZONAWS

Loam: \( 0.4 \times 80 = 32 \, \textkg \) - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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🔥 Popular Posts

\(\int 1 \, dx = x\).
Combine: \(rac{1}{2}x^4 - 2x^2 + x + C\), where \(C\) is the constant...
#### \(rac{1}{2}x^4 - 2x^2 + x + C\)
If \(\log_2(x) + \log_2(8) = 5\), what is the value of \(x\)?
Use logarithmic identity: \(\log_2(x) + \log_2(8) = \log_2(8x)\).
So \(\log_2(8x) = 5\).
Convert to exponential form: \(8x = 2^5 = 32\).
\(8x = 32\) â \(x = rac{32}{8} = 4\).
Use the Pythagorean Theorem: \(c^2 = a^2 + b^2\).
\(c^2 = 9^2 + 12^2 = 81 + 144 = 225\).

📝 Recent Posts

The altitude corresponding to a side is $ h = \frac{2A}{\text{side}} $...
h_{\text{longest}} = \frac{2 \cdot 84}{13} = \frac{168}{13} \approx 12...
Thus, the length of the longest altitude is $ \boxed{\frac{168}{13}} $...
Question: An equilateral triangle has a perimeter of $ 36 $ cm. If eac...
Solution: The original side length of the equilateral triangle is $ \f...
Original area:
A_1 = \frac{\sqrt{3}}{4} \cdot 12^2 = \frac{\sqrt{3}}{4} \cdot 144 = 3...
New side length: $ 12 + 2 = 14 $ cm. New area:
A_2 = \frac{\sqrt{3}}{4} \cdot 14^2 = \frac{\sqrt{3}}{4} \cdot 196 = 4...
\Delta A = A_2 - A_1 = 49\sqrt{3} - 36\sqrt{3} = 13\sqrt{3}

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