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Home » Multiply \( 2 \) by \( t^2 + 1 \) to get \( 2t^2 + 2 \). - AMAZONAWS

Multiply \( 2 \) by \( t^2 + 1 \) to get \( 2t^2 + 2 \). - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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3t^2 - 2t + 5 = 20
Subtract 20 from both sides:
3t^2 - 2t + 5 - 20 = 0
3t^2 - 2t - 15 = 0
This is a quadratic equation in the form \( at^2 + bt + c = 0 \), wher...
t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
Substitute the values of \( a \), \( b \), and \( c \):
t = \frac{-(-2) \pm \sqrt{(-2)^2 - 4 \cdot 3 \cdot (-15)}}{2 \cdot 3}
t = \frac{2 \pm \sqrt{4 + 180}}{6}
t = \frac{2 \pm \sqrt{184}}{6}

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