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Home » So Armand = (1/0.7)x ≈ 1.4286x. - AMAZONAWS

So Armand = (1/0.7)x ≈ 1.4286x. - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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$ a = \frac{120}{112.5} = 1.07 $ m/s²
#### 1.07
An ichthyologist tracks the population of a coral reef fish species, w...
The half-life formula is $ t_{1/2} = \frac{\ln(2)}{k} $.
Given $ t_{1/2} = 4 $ years:
$ 4 = \frac{\ln(2)}{k} $
$ k = \frac{\ln(2)}{4} \approx \frac{0.693}{4} = 0.173 $ per year
#### 0.173
A search and rescue robot moves at 2.5 m/s but encounters a 30° inclin...
The speed reduction is $ 2.5 \times 0.15 = 0.375 $ m/s.

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