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Home » Solve for \( x \) in the equation \( 2^x+1 = 32 \). - AMAZONAWS

Solve for \( x \) in the equation \( 2^x+1 = 32 \). - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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where \( R(v) \) is the remainder and has degree less than 2, so let \...
Divide the leading term \( v^4 \) by \( v^2 \), giving \( v^2 \).
Multiply \( v^2(v^2 + 1) = v^4 + v^2 \).
Subtract: \( (v^4 + 3v + 1) - (v^4 + v^2) = -v^2 + 3v + 1 \).
Divide \( -v^2 \) by \( v^2 \), giving \(-1\).
Multiply: \(-1(v^2 + 1) = -v^2 - 1\).
Subtract: \((-v^2 + 3v + 1) - (-v^2 - 1) = 3v + 2\).
\boxed{3v + 2}.
Solve for \( x \) in the equation \(\frac{x + 2}{x - 2} + \frac{x - 2}...
a = \frac{x + 2}{x - 2}, \quad \frac{x - 2}{x + 2} = \frac{1}{a}.

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