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\textAnstieg = 650.000 - 500.000 = 150.000 - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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🔥 Popular Posts

z^4 + 4z^2 + 4 = (z^2 + 2)^2 = 0
So indeed, \( (z^2 + 2)^2 = 0 \), so roots are \( z = \pm i\sqrt{2} \)...
Alternatively, interpret as sum over all **solutions** (with multiplic...
But here, the equation \( (z^2 + 2)^2 = 0 \) has roots:
z = i\sqrt{2}, i\sqrt{2}, -i\sqrt{2}, -i\sqrt{2}
Four roots total (with multiplicity 2 each), but real part of each is...
Since the real part is linear, we can sum the real parts:
\text{Re}(i\sqrt{2}) + \text{Re}(i\sqrt{2}) + \text{Re}(-i\sqrt{2}) +...
Thus, the sum is \( \boxed{0} \).
Answer:

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f(a + b) = f(a) + f(b)
So $ f $ is additive. Also, from the multiplicative condition:
So $ f $ is both additive and multiplicative. These are very restricti...
Known result: The only functions $ f : \mathbb{R} \to \mathbb{R} $ tha...
$ f(x) = 0 $ for all $ x $
$ f(x) = x $ for all $ x $
Let’s verify both:
$ f(x) = 0 $: $ f(a + b + c) = 0 = 0 + 0 + 0 = f(a) + f(b) + f(c) $, a...
$ f(x) = x $: $ f(a + b + c) = a + b + c = f(a) + f(b) + f(c) $, and $...
Are there any others? Suppose $ f $ is additive and multiplicative. Th...

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