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Home » Thus, \( h(x) = x^2 + 4x + 3 \). - AMAZONAWS

Thus, \( h(x) = x^2 + 4x + 3 \). - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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Try: \( S_n = 90 \), a=5, d=5
\( 90 = \frac{n}{2}(10 + (n−1)5) = \frac{n}{2}(5n + 5) = \frac{5n(n+1)...
\( 180 = 5n(n+1) → n(n+1) = 36 → n² + n − 36 = 0 → n = [-1±√145]/2 — n...
Try: Sₙ = 60, a=3, d=3
\( 60 = \frac{n}{2}(6 + (n−1)3) = \frac{n}{2}(3n + 3) = \frac{3n(n+1)}...
\( 120 = 3n(n+1) → n(n+1) = 40 → n ≈ 6.3 → n=6: 6×7=42>40, n=5:5×6=30<...
n(n+1)=42 → n=6: 6×7=42 → then \( \frac{3×6×7}{2} = \frac{126}{2} = 63...
Set Sₙ = 63, a=3, d=3
\( 63 = \frac{n}{2}(6 + (n−1)3) = \frac{n}{2}(3n + 3) = \frac{3n(n+1)}...
\( 126 = 3n(n+1) → n(n+1) = 42 → n=6:6×7=42 → yes!

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