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📅 March 6, 2026 👤 scraface

Mar 06, 2026

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Initially:
Base = 5 m, hypotenuse = 13 m
Height = \( \sqrt{13^2 - 5^2} = \sqrt{169 - 25} = \sqrt{144} = 12 \) m
After sliding: base = 7 m
New height = \( \sqrt{13^2 - 7^2} = \sqrt{169 - 49} = \sqrt{120} = 2\s...
But \( 2\sqrt{30} \approx 10.95 \), so distance slid down:
- 2\sqrt{30} \approx 12 - 10.95 = 1.05
Exact:
\Delta h = 12 - \sqrt{120} = 12 - 2\sqrt{30}
But compute exactly:

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