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z = 90^\circ, 270^\circ. - AMAZONAWS

📅 March 5, 2026 👤 scraface

Mar 05, 2026

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📌 Now compute \(3025 \mod 11\). First, reduce 55 modulo 11:

📌 \(55 \div 11 = 5\), so \(55 \equiv 0 \pmod{11}\).

📌 Then \(55^2 \equiv 0^2 = 0 \pmod{11}\).

📌 Thus, \(3025 \equiv 0 \pmod{11}\).

📌 Alternatively, since \(55 \equiv 0 \mod 11\), the square is divisible by \(11^2\), hence by 11.

📌 Therefore, the remainder is \(\boxed{0}\).

📌 An emerging technology researcher exploring base systems in quantum computing asks: What is the base-ten number represented by the base-nine number \(321_9\)?

📌 To convert \(321_9\) to base ten, expand using powers of 9:

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